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![]() The voltmeter measures the electric potential difference between the electrodes, and the ammeter measures the photocurrent. The anode and cathode are enclosed in an evacuated glass tube. And radio waves (really long wavelength) diffract more than X-rays (really short wavelengths). 1: An experimental setup to study the photoelectric effect. where is the density of the material in which the sound wave travels, in units of kg/m 3. The relationship between the intensity of a sound wave and its pressure amplitude (or pressure variation p) is. Hence red light (long wavelength) diffracts more than blue light (short wavelength). The intensity of a sound depends upon its pressure amplitude. In short, the angle of diffraction is directly proportional to the size of the wavelength. Conversely, as the wavelength decreases, the angle of diffraction decreases. (A similar formula for destructive interference exists.)įrom either formula, however, it's clear that as the wavelength increases, the angle of diffraction increases, since these variables are on opposite sides of the equal sign. The formula for diffraction shows a direct relationship between the angle of diffraction (theta) and wavelength:ĭ (sin theta) = m (wavelength) -> for constructive interference Hence, light diffracts more through small openings than through larger openings. ![]() For non-monochromatic waves, the intensity contributions of. And the area of cross-section is 100 square meters. Intensities in Optical Physics c is the vacuum velocity of light, and n is the refractive index. Q.2: Find out the power of a wave whose intensity is given as 30 ×105 Watt per square meter. Moreover, waves diffract best when the size of the diffraction opening (or grting or groove) corresponds to the size of the wavelength. Therefore the intensity will be 0.57 × 103 Watt per square meter. A) the procedure to be followed B) how the wavelength of the light falling on the LDR is determined C) how a measure of the intensity can be obtained from the LDR D) the range and precision of any intruments that would be used E) the factors that would need to be controlled to ensure that it is a valid test F) any safety precautions you would. Since light waves are small (on the order of 400 to 700 nanometers), diffraction only occurs through small openings or over small grooves. The bending is the result of light waves "squeezing" through small openings or "curving" around sharp edges. And the area of cross-section is 100 square meters. In contrast, diffraction occurs when light bends in the same medium. Therefore the intensity will be 0.57 × 103 Watt per square meter. The SI unit for intensity is watts per square meter ((W/m2)). Refraction occurs when light bends as it crosses a boundary between two different mediums, each with a different index of refraction. The definition of intensity is valid for any energy in transit, including that carried by waves.
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